Base | Representation |
---|---|
bin | 10100011001110110001… |
… | …111000111010110010001 |
3 | 11222001011202110002121121 |
4 | 110121312033013112101 |
5 | 140433042102342431 |
6 | 2552045142522241 |
7 | 203205260646106 |
oct | 24316617072621 |
9 | 4861152402547 |
10 | 1402143012241 |
11 | 4a07111a4094 |
12 | 1a78b2a36381 |
13 | a22b58a465a |
14 | 4bc15090aad |
15 | 26716371611 |
hex | 146763c7591 |
1402143012241 has 2 divisors, whose sum is σ = 1402143012242. Its totient is φ = 1402143012240.
The previous prime is 1402143012239. The next prime is 1402143012251. The reversal of 1402143012241 is 1422103412041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1382823124225 + 19319888016 = 1175935^2 + 138996^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402143012241 - 21 = 1402143012239 is a prime.
Together with 1402143012239, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1402143012251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701071506120 + 701071506121.
It is an arithmetic number, because the mean of its divisors is an integer number (701071506121).
Almost surely, 21402143012241 is an apocalyptic number.
It is an amenable number.
1402143012241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402143012241 is an equidigital number, since it uses as much as digits as its factorization.
1402143012241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1402143012241 its reverse (1422103412041), we get a palindrome (2824246424282).
The spelling of 1402143012241 in words is "one trillion, four hundred two billion, one hundred forty-three million, twelve thousand, two hundred forty-one".
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