Base | Representation |
---|---|
bin | 10100011001110110010… |
… | …000010111101000101101 |
3 | 11222001011210001210201121 |
4 | 110121312100113220231 |
5 | 140433042143403401 |
6 | 2552045153540541 |
7 | 203205263515636 |
oct | 24316620275055 |
9 | 4861153053647 |
10 | 1402143341101 |
11 | 4a07113a9178 |
12 | 1a78b2b74751 |
13 | a22b598b249 |
14 | 4bc1513888d |
15 | 267163d8ca1 |
hex | 14676417a2d |
1402143341101 has 2 divisors, whose sum is σ = 1402143341102. Its totient is φ = 1402143341100.
The previous prime is 1402143341087. The next prime is 1402143341119. The reversal of 1402143341101 is 1011433412041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1402128333225 + 15007876 = 1184115^2 + 3874^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402143341101 - 29 = 1402143340589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1402143342101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701071670550 + 701071670551.
It is an arithmetic number, because the mean of its divisors is an integer number (701071670551).
Almost surely, 21402143341101 is an apocalyptic number.
It is an amenable number.
1402143341101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402143341101 is an equidigital number, since it uses as much as digits as its factorization.
1402143341101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1402143341101 its reverse (1011433412041), we get a palindrome (2413576753142).
The spelling of 1402143341101 in words is "one trillion, four hundred two billion, one hundred forty-three million, three hundred forty-one thousand, one hundred one".
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