Base | Representation |
---|---|
bin | 10100011001111010010… |
… | …011011001000010001001 |
3 | 11222001100111211112102012 |
4 | 110121322103121002021 |
5 | 140433212034221441 |
6 | 2552100021145305 |
7 | 203210046621044 |
oct | 24317223310211 |
9 | 4861314745365 |
10 | 1402211242121 |
11 | 4a0746766218 |
12 | 1a791185b235 |
13 | a22c6a73571 |
14 | 4bc20171c5b |
15 | 2671c34c9eb |
hex | 1467a4d9089 |
1402211242121 has 2 divisors, whose sum is σ = 1402211242122. Its totient is φ = 1402211242120.
The previous prime is 1402211242111. The next prime is 1402211242141. The reversal of 1402211242121 is 1212421122041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1290066627721 + 112144614400 = 1135811^2 + 334880^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1402211242121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402211242111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701105621060 + 701105621061.
It is an arithmetic number, because the mean of its divisors is an integer number (701105621061).
Almost surely, 21402211242121 is an apocalyptic number.
It is an amenable number.
1402211242121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402211242121 is an equidigital number, since it uses as much as digits as its factorization.
1402211242121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 23.
Adding to 1402211242121 its reverse (1212421122041), we get a palindrome (2614632364162).
The spelling of 1402211242121 in words is "one trillion, four hundred two billion, two hundred eleven million, two hundred forty-two thousand, one hundred twenty-one".
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