Base | Representation |
---|---|
bin | 10100011001111011100… |
… | …000010101100101101111 |
3 | 11222001101220210022210121 |
4 | 110121323200111211233 |
5 | 140433232220204403 |
6 | 2552102021345411 |
7 | 203210413231423 |
oct | 24317340254557 |
9 | 4861356708717 |
10 | 1402231413103 |
11 | 4a0757092a54 |
12 | 1a7918568267 |
13 | a22cacb6761 |
14 | 4bc22b02b83 |
15 | 2671ded43bd |
hex | 1467b81596f |
1402231413103 has 4 divisors (see below), whose sum is σ = 1402240528368. Its totient is φ = 1402222297840.
The previous prime is 1402231413101. The next prime is 1402231413133. The reversal of 1402231413103 is 3013141322041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1402231413103 - 21 = 1402231413101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1402231413101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4322851 + ... + 4635892.
It is an arithmetic number, because the mean of its divisors is an integer number (350560132092).
Almost surely, 21402231413103 is an apocalyptic number.
1402231413103 is a deficient number, since it is larger than the sum of its proper divisors (9115265).
1402231413103 is an equidigital number, since it uses as much as digits as its factorization.
1402231413103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9115264.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1402231413103 its reverse (3013141322041), we get a palindrome (4415372735144).
The spelling of 1402231413103 in words is "one trillion, four hundred two billion, two hundred thirty-one million, four hundred thirteen thousand, one hundred three".
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