140223344214131 has 2 divisors, whose sum is σ = 140223344214132. Its totient is φ = 140223344214130.

The previous prime is 140223344214103. The next prime is 140223344214157. The reversal of 140223344214131 is 131412443322041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140223344214131 - 2³⁴ = 140206164344947 is a prime.

It is a super-2 number, since 2×140223344214131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140223344214091 and 140223344214100.

It is not a weakly prime, because it can be changed into another prime (140223340214131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70111672107065 + 70111672107066.

It is an arithmetic number, because the mean of its divisors is an integer number (70111672107066).

Almost surely, 2^{140223344214131} is an apocalyptic number.

140223344214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

140223344214131 is an equidigital number, since it uses as much as digits as its factorization.

140223344214131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 140223344214131 its reverse (131412443322041), we get a palindrome (271635787536172).

The spelling of 140223344214131 in words is "one hundred forty trillion, two hundred twenty-three billion, three hundred forty-four million, two hundred fourteen thousand, one hundred thirty-one".