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1402248433 is a prime number
BaseRepresentation
bin101001110010100…
…1001110011110001
310121201120121020011
41103211021303301
510332433422213
6351051014521
746514625565
oct12345116361
93551517204
101402248433
1165a595003
1233173a441
13194688001
14d43396a5
158318b03d
hex53949cf1

1402248433 has 2 divisors, whose sum is σ = 1402248434. Its totient is φ = 1402248432.

The previous prime is 1402248371. The next prime is 1402248437. The reversal of 1402248433 is 3348422041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1165334769 + 236913664 = 34137^2 + 15392^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402248433 - 225 = 1368694001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1402248395 and 1402248404.

It is not a weakly prime, because it can be changed into another prime (1402248437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701124216 + 701124217.

It is an arithmetic number, because the mean of its divisors is an integer number (701124217).

Almost surely, 21402248433 is an apocalyptic number.

It is an amenable number.

1402248433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402248433 is an equidigital number, since it uses as much as digits as its factorization.

1402248433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

The square root of 1402248433 is about 37446.6077635879. The cubic root of 1402248433 is about 1119.2875020319.

The spelling of 1402248433 in words is "one billion, four hundred two million, two hundred forty-eight thousand, four hundred thirty-three".