Base | Representation |
---|---|
bin | 1100110000001101111111… |
… | …1011111000010011100110 |
3 | 1211122112121020121021112012 |
4 | 3030003133323320103212 |
5 | 3314221120222123223 |
6 | 45453510024554222 |
7 | 2645044241446154 |
oct | 314033773702346 |
9 | 54575536537465 |
10 | 14022530270438 |
11 | 4516a158532a8 |
12 | 16a57b1022972 |
13 | 7a941b8c9111 |
14 | 3669a08043d4 |
15 | 194b58d73c78 |
hex | cc0dfef84e6 |
14022530270438 has 4 divisors (see below), whose sum is σ = 21033795405660. Its totient is φ = 7011265135218.
The previous prime is 14022530270393. The next prime is 14022530270453. The reversal of 14022530270438 is 83407203522041.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 14022530270395 and 14022530270404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3505632567608 + ... + 3505632567611.
It is an arithmetic number, because the mean of its divisors is an integer number (5258448851415).
Almost surely, 214022530270438 is an apocalyptic number.
14022530270438 is a deficient number, since it is larger than the sum of its proper divisors (7011265135222).
14022530270438 is an equidigital number, since it uses as much as digits as its factorization.
14022530270438 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7011265135221.
The product of its (nonzero) digits is 322560, while the sum is 41.
Adding to 14022530270438 its reverse (83407203522041), we get a palindrome (97429733792479).
The spelling of 14022530270438 in words is "fourteen trillion, twenty-two billion, five hundred thirty million, two hundred seventy thousand, four hundred thirty-eight".
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