Base | Representation |
---|---|
bin | 11010000111101011… |
… | …11110010101110101 |
3 | 1100012021222112012121 |
4 | 31003311332111311 |
5 | 212204404434331 |
6 | 10235300115541 |
7 | 1004335406302 |
oct | 150365762565 |
9 | 40167875177 |
10 | 14023124341 |
11 | 5a46762966 |
12 | 2874395bb1 |
13 | 1426347415 |
14 | 9705b60a9 |
15 | 57119ec11 |
hex | 343d7e575 |
14023124341 has 2 divisors, whose sum is σ = 14023124342. Its totient is φ = 14023124340.
The previous prime is 14023124327. The next prime is 14023124351. The reversal of 14023124341 is 14342132041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13143705316 + 879419025 = 114646^2 + 29655^2 .
It is an emirp because it is prime and its reverse (14342132041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14023124341 - 215 = 14023091573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14023124351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011562170 + 7011562171.
It is an arithmetic number, because the mean of its divisors is an integer number (7011562171).
Almost surely, 214023124341 is an apocalyptic number.
It is an amenable number.
14023124341 is a deficient number, since it is larger than the sum of its proper divisors (1).
14023124341 is an equidigital number, since it uses as much as digits as its factorization.
14023124341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14023124341 its reverse (14342132041), we get a palindrome (28365256382).
The spelling of 14023124341 in words is "fourteen billion, twenty-three million, one hundred twenty-four thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •