140234011432013 has 4 divisors (see below), whose sum is σ = 140235691991100. Its totient is φ = 140232330872928.

The previous prime is 140234011432007. The next prime is 140234011432019. The reversal of 140234011432013 is 310234110432041.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (140234011432007) and next prime (140234011432019).

It can be written as a sum of positive squares in 2 ways, for example, as 18336226254724 + 121897785177289 = 4282082^2 + 11040733^2 .

It is a cyclic number.

It is not a de Polignac number, because 140234011432013 - 2¹⁸ = 140234011169869 is a prime.

It is a super-3 number, since 3×140234011432013³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140234011432019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 840154370 + ... + 840321267.

It is an arithmetic number, because the mean of its divisors is an integer number (35058922997775).

Almost surely, 2^{140234011432013} is an apocalyptic number.

It is an amenable number.

140234011432013 is a deficient number, since it is larger than the sum of its proper divisors (1680559087).

140234011432013 is an equidigital number, since it uses as much as digits as its factorization.

140234011432013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1680559086.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 140234011432013 its reverse (310234110432041), we get a palindrome (450468121864054).

The spelling of 140234011432013 in words is "one hundred forty trillion, two hundred thirty-four billion, eleven million, four hundred thirty-two thousand, thirteen".