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140240033131271 is a prime number
BaseRepresentation
bin11111111000110000101101…
…010110111010101100000111
3200101112211001000221000011012
4133320300231112322230013
5121340143041440200041
61214133214250032435
741353002520163363
oct3770605526725407
9611484030830135
10140240033131271
114075951171a4a7
121388b55b41871b
136033769912418
14268b9221222a3
151132e722de3eb
hex7f8c2d5bab07

140240033131271 has 2 divisors, whose sum is σ = 140240033131272. Its totient is φ = 140240033131270.

The previous prime is 140240033131249. The next prime is 140240033131391. The reversal of 140240033131271 is 172131330042041.

It is a weak prime.

It is an emirp because it is prime and its reverse (172131330042041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140240033131271 - 234 = 140222853262087 is a prime.

It is a super-2 number, since 2×1402400331312712 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140240033131201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120016565635 + 70120016565636.

It is an arithmetic number, because the mean of its divisors is an integer number (70120016565636).

Almost surely, 2140240033131271 is an apocalyptic number.

140240033131271 is a deficient number, since it is larger than the sum of its proper divisors (1).

140240033131271 is an equidigital number, since it uses as much as digits as its factorization.

140240033131271 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

The spelling of 140240033131271 in words is "one hundred forty trillion, two hundred forty billion, thirty-three million, one hundred thirty-one thousand, two hundred seventy-one".