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140241313433101 is a prime number
BaseRepresentation
bin11111111000110001111001…
…101010111000011000001101
3200101112221100021001002002111
4133320301321222320120031
5121340203202214324401
61214133545303224021
741353046324442646
oct3770617152703015
9611487307032074
10140241313433101
114075a009393191
121388b858148011
136033911c4147a
14268ba041966cd
151132ee98dce51
hex7f8c79ab860d

140241313433101 has 2 divisors, whose sum is σ = 140241313433102. Its totient is φ = 140241313433100.

The previous prime is 140241313433029. The next prime is 140241313433161. The reversal of 140241313433101 is 101334313142041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137431097056201 + 2810216376900 = 11723101^2 + 1676370^2 .

It is a cyclic number.

It is not a de Polignac number, because 140241313433101 - 217 = 140241313302029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140241313433161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120656716550 + 70120656716551.

It is an arithmetic number, because the mean of its divisors is an integer number (70120656716551).

Almost surely, 2140241313433101 is an apocalyptic number.

It is an amenable number.

140241313433101 is a deficient number, since it is larger than the sum of its proper divisors (1).

140241313433101 is an equidigital number, since it uses as much as digits as its factorization.

140241313433101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 140241313433101 its reverse (101334313142041), we get a palindrome (241575626575142).

The spelling of 140241313433101 in words is "one hundred forty trillion, two hundred forty-one billion, three hundred thirteen million, four hundred thirty-three thousand, one hundred one".