14024201123 has 4 divisors (see below), whose sum is σ = 14073756888. Its totient is φ = 13974645360.

The previous prime is 14024201117. The next prime is 14024201129. The reversal of 14024201123 is 32110242041.

14024201123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32110242041 = 19 ⋅1690012739.

It is an interprime number because it is at equal distance from previous prime (14024201117) and next prime (14024201129).

It is a cyclic number.

It is not a de Polignac number, because 14024201123 - 2⁸ = 14024200867 is a prime.

It is a super-2 number, since 2×14024201123² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14024201095 and 14024201104.

It is not an unprimeable number, because it can be changed into a prime (14024201129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24777458 + ... + 24778023.

It is an arithmetic number, because the mean of its divisors is an integer number (3518439222).

Almost surely, 2^14024201123 is an apocalyptic number.

14024201123 is a deficient number, since it is larger than the sum of its proper divisors (49555765).

14024201123 is an equidigital number, since it uses as much as digits as its factorization.

14024201123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49555764.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 14024201123 its reverse (32110242041), we get a palindrome (46134443164).

The spelling of 14024201123 in words is "fourteen billion, twenty-four million, two hundred one thousand, one hundred twenty-three".