Search a number
-
+
14025001 = 26353327
BaseRepresentation
bin110101100000…
…000100101001
3222101112200111
4311200010221
512042300001
61220334321
7230132134
oct65400451
928345614
1014025001
117a0a211
1248443a1
132ba0923
141c1121b
151370851
hexd60129

14025001 has 4 divisors (see below), whose sum is σ = 14078592. Its totient is φ = 13971412.

The previous prime is 14024999. The next prime is 14025007. The reversal of 14025001 is 10052041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10052041 = 25739113.

It is a cyclic number.

It is not a de Polignac number, because 14025001 - 21 = 14024999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14025007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26401 + ... + 26926.

It is an arithmetic number, because the mean of its divisors is an integer number (3519648).

Almost surely, 214025001 is an apocalyptic number.

It is an amenable number.

14025001 is a deficient number, since it is larger than the sum of its proper divisors (53591).

14025001 is an equidigital number, since it uses as much as digits as its factorization.

14025001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53590.

The product of its (nonzero) digits is 40, while the sum is 13.

The square root of 14025001 is about 3744.9967957263. The cubic root of 14025001 is about 241.1576076894.

Adding to 14025001 its reverse (10052041), we get a palindrome (24077042).

The spelling of 14025001 in words is "fourteen million, twenty-five thousand, one".

Divisors: 1 263 53327 14025001