Base | Representation |
---|---|
bin | 11010000111111011… |
… | …11011111001011001 |
3 | 1100012102220120020002 |
4 | 31003331323321121 |
5 | 212210423231411 |
6 | 10235412542345 |
7 | 1004362221251 |
oct | 150375737131 |
9 | 40172816202 |
10 | 14025211481 |
11 | 5a47958a76 |
12 | 28750219b5 |
13 | 14268c8408 |
14 | 97099a961 |
15 | 57146333b |
hex | 343f7be59 |
14025211481 has 2 divisors, whose sum is σ = 14025211482. Its totient is φ = 14025211480.
The previous prime is 14025211471. The next prime is 14025211493. The reversal of 14025211481 is 18411252041.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10624455625 + 3400755856 = 103075^2 + 58316^2 .
It is a cyclic number.
It is not a de Polignac number, because 14025211481 - 222 = 14021017177 is a prime.
It is a super-2 number, since 2×140252114812 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (14025211411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012605740 + 7012605741.
It is an arithmetic number, because the mean of its divisors is an integer number (7012605741).
Almost surely, 214025211481 is an apocalyptic number.
It is an amenable number.
14025211481 is a deficient number, since it is larger than the sum of its proper divisors (1).
14025211481 is an equidigital number, since it uses as much as digits as its factorization.
14025211481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 29.
The spelling of 14025211481 in words is "fourteen billion, twenty-five million, two hundred eleven thousand, four hundred eighty-one".
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