Base | Representation |
---|---|
bin | 11010000111111011… |
… | …11011111010011011 |
3 | 1100012102220120022112 |
4 | 31003331323322123 |
5 | 212210423232142 |
6 | 10235412542535 |
7 | 1004362221404 |
oct | 150375737233 |
9 | 40172816275 |
10 | 14025211547 |
11 | 5a47959026 |
12 | 2875021a4b |
13 | 14268c8459 |
14 | 97099a9ab |
15 | 571463382 |
hex | 343f7be9b |
14025211547 has 2 divisors, whose sum is σ = 14025211548. Its totient is φ = 14025211546.
The previous prime is 14025211493. The next prime is 14025211631. The reversal of 14025211547 is 74511252041.
It is a weak prime.
It is an emirp because it is prime and its reverse (74511252041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14025211547 - 224 = 14008434331 is a prime.
It is not a weakly prime, because it can be changed into another prime (14025214547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012605773 + 7012605774.
It is an arithmetic number, because the mean of its divisors is an integer number (7012605774).
Almost surely, 214025211547 is an apocalyptic number.
14025211547 is a deficient number, since it is larger than the sum of its proper divisors (1).
14025211547 is an equidigital number, since it uses as much as digits as its factorization.
14025211547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11200, while the sum is 32.
Adding to 14025211547 its reverse (74511252041), we get a palindrome (88536463588).
The spelling of 14025211547 in words is "fourteen billion, twenty-five million, two hundred eleven thousand, five hundred forty-seven".
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