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140252124343 = 711975382033
BaseRepresentation
bin1000001010011110101…
…1011001010010110111
3111102000102010010022211
42002213223121102313
54244214020434333
6144233025434251
713063402246462
oct2024753312267
9442012103284
10140252124343
1154531738971
122322219b987
13102c1b995b6
146b06cdc2d9
1539ace24ecd
hex20a7ad94b7

140252124343 has 4 divisors (see below), whose sum is σ = 142227506448. Its totient is φ = 138276742240.

The previous prime is 140252124301. The next prime is 140252124367. The reversal of 140252124343 is 343421252041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140252124343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140252124043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 987690946 + ... + 987691087.

It is an arithmetic number, because the mean of its divisors is an integer number (35556876612).

Almost surely, 2140252124343 is an apocalyptic number.

140252124343 is a deficient number, since it is larger than the sum of its proper divisors (1975382105).

140252124343 is an equidigital number, since it uses as much as digits as its factorization.

140252124343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1975382104.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 140252124343 its reverse (343421252041), we get a palindrome (483673376384).

The spelling of 140252124343 in words is "one hundred forty billion, two hundred fifty-two million, one hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 71 1975382033 140252124343