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14025400551 = 3225723772551
BaseRepresentation
bin11010000111111101…
…01010000011100111
31100012110021011120200
431003332222003213
5212211000304201
610235421001543
71004363636421
oct150376520347
940173234520
1014025400551
115a47a78028
1228750b32b3
1314269634a6
14970a09811
1557149e386
hex343faa0e7

14025400551 has 24 divisors (see below), whose sum is σ = 20354272224. Its totient is φ = 9306316800.

The previous prime is 14025400541. The next prime is 14025400553. The reversal of 14025400551 is 15500452041.

It is not a de Polignac number, because 14025400551 - 222 = 14021206247 is a prime.

It is a super-2 number, since 2×140254005512 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14025400553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5496726 + ... + 5499276.

It is an arithmetic number, because the mean of its divisors is an integer number (848094676).

Almost surely, 214025400551 is an apocalyptic number.

14025400551 is a deficient number, since it is larger than the sum of its proper divisors (6328871673).

14025400551 is a wasteful number, since it uses less digits than its factorization.

14025400551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5191 (or 5188 counting only the distinct ones).

The product of its (nonzero) digits is 4000, while the sum is 27.

Adding to 14025400551 its reverse (15500452041), we get a palindrome (29525852592).

The spelling of 14025400551 in words is "fourteen billion, twenty-five million, four hundred thousand, five hundred fifty-one".

Divisors: 1 3 9 257 771 2313 2377 2551 7131 7653 21393 22959 610889 655607 1832667 1966821 5498001 5900463 6063727 18191181 54573543 1558377839 4675133517 14025400551