140274112471 has 4 divisors (see below), whose sum is σ = 140275016512. Its totient is φ = 140273208432.

The previous prime is 140274112463. The next prime is 140274112481. The reversal of 140274112471 is 174211472041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 174211472041 = 10321 ⋅16879321.

It is a cyclic number.

It is not a de Polignac number, because 140274112471 - 2³ = 140274112463 is a prime.

It is a super-3 number, since 3×140274112471³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140274112481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153606 + ... + 551491.

It is an arithmetic number, because the mean of its divisors is an integer number (35068754128).

Almost surely, 2^140274112471 is an apocalyptic number.

140274112471 is a deficient number, since it is larger than the sum of its proper divisors (904041).

140274112471 is an equidigital number, since it uses as much as digits as its factorization.

140274112471 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 904040.

The product of its (nonzero) digits is 12544, while the sum is 34.

The spelling of 140274112471 in words is "one hundred forty billion, two hundred seventy-four million, one hundred twelve thousand, four hundred seventy-one".