Base | Representation |
---|---|
bin | 1100110000101010010100… |
… | …0110110001000001100001 |
3 | 1211200021020002212021100121 |
4 | 3030022211012301001201 |
5 | 3314332203044444131 |
6 | 45501204302120241 |
7 | 2645433531350344 |
oct | 314124506610141 |
9 | 54607202767317 |
10 | 14030133203041 |
11 | 451a16747907a |
12 | 16a7173280081 |
13 | 7aa060ab66c7 |
14 | 3670c246c45b |
15 | 194e51589911 |
hex | cc2a51b1061 |
14030133203041 has 4 divisors (see below), whose sum is σ = 14294852697492. Its totient is φ = 13765413708592.
The previous prime is 14030133203029. The next prime is 14030133203069. The reversal of 14030133203041 is 14030233103041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11743444850641 + 2286688352400 = 3426871^2 + 1512180^2 .
It is a cyclic number.
It is not a de Polignac number, because 14030133203041 - 219 = 14030132678753 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14030133202997 and 14030133203015.
It is not an unprimeable number, because it can be changed into a prime (14030133273041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132359747146 + ... + 132359747251.
It is an arithmetic number, because the mean of its divisors is an integer number (3573713174373).
Almost surely, 214030133203041 is an apocalyptic number.
It is an amenable number.
14030133203041 is a deficient number, since it is larger than the sum of its proper divisors (264719494451).
14030133203041 is an equidigital number, since it uses as much as digits as its factorization.
14030133203041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264719494450.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14030133203041 its reverse (14030233103041), we get a palindrome (28060366306082).
The spelling of 14030133203041 in words is "fourteen trillion, thirty billion, one hundred thirty-three million, two hundred three thousand, forty-one".
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