Base | Representation |
---|---|
bin | 11111111001101010100011… |
… | …010001001010110010001011 |
3 | 200101202202100102121102210201 |
4 | 133321222203101022302023 |
5 | 121342202241031043323 |
6 | 1214221525210353031 |
7 | 41360331562261231 |
oct | 3771524321126213 |
9 | 611682312542721 |
10 | 140302140877963 |
11 | 40782892946879 |
12 | 1389b5b312b777 |
13 | 6039586c404ac |
14 | 26909348ba951 |
15 | 11348a9ad98ad |
hex | 7f9aa344ac8b |
140302140877963 has 2 divisors, whose sum is σ = 140302140877964. Its totient is φ = 140302140877962.
The previous prime is 140302140877961. The next prime is 140302140877993. The reversal of 140302140877963 is 369778041203041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140302140877963 - 21 = 140302140877961 is a prime.
It is a super-3 number, since 3×1403021408779633 (a number of 43 digits) contains 333 as substring.
Together with 140302140877961, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (140302140877961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70151070438981 + 70151070438982.
It is an arithmetic number, because the mean of its divisors is an integer number (70151070438982).
Almost surely, 2140302140877963 is an apocalyptic number.
140302140877963 is a deficient number, since it is larger than the sum of its proper divisors (1).
140302140877963 is an equidigital number, since it uses as much as digits as its factorization.
140302140877963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6096384, while the sum is 55.
The spelling of 140302140877963 in words is "one hundred forty trillion, three hundred two billion, one hundred forty million, eight hundred seventy-seven thousand, nine hundred sixty-three".
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