Base | Representation |
---|---|
bin | 1100110000101010101110… |
… | …1010000000110011001111 |
3 | 1211200021111202122220212112 |
4 | 3030022223222000303033 |
5 | 3314332414213342444 |
6 | 45501223225454235 |
7 | 2645436334456211 |
oct | 314125352006317 |
9 | 54607452586775 |
10 | 14030243105999 |
11 | 451a21351386a |
12 | 16a71a404137b |
13 | 7aa07a7b6843 |
14 | 3670d2cba5b1 |
15 | 194e5b04869e |
hex | cc2aba80ccf |
14030243105999 has 4 divisors (see below), whose sum is σ = 14100746840400. Its totient is φ = 13959739371600.
The previous prime is 14030243105981. The next prime is 14030243106037. The reversal of 14030243105999 is 99950134203041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14030243105999 is a prime.
It is a super-2 number, since 2×140302431059992 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14030243105909) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35251866902 + ... + 35251867299.
It is an arithmetic number, because the mean of its divisors is an integer number (3525186710100).
Almost surely, 214030243105999 is an apocalyptic number.
14030243105999 is a deficient number, since it is larger than the sum of its proper divisors (70503734401).
14030243105999 is an equidigital number, since it uses as much as digits as its factorization.
14030243105999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70503734400.
The product of its (nonzero) digits is 1049760, while the sum is 50.
The spelling of 14030243105999 in words is "fourteen trillion, thirty billion, two hundred forty-three million, one hundred five thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •