140310014301121 has 4 divisors (see below), whose sum is σ = 160354302058432. Its totient is φ = 120265726543812.

The previous prime is 140310014301103. The next prime is 140310014301151. The reversal of 140310014301121 is 121103410013041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140310014301121 is a prime.

It is a super-2 number, since 2×140310014301121² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140310014301092 and 140310014301101.

It is not an unprimeable number, because it can be changed into a prime (140310014301101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10022143878645 + ... + 10022143878658.

It is an arithmetic number, because the mean of its divisors is an integer number (40088575514608).

Almost surely, 2^{140310014301121} is an apocalyptic number.

It is an amenable number.

140310014301121 is a deficient number, since it is larger than the sum of its proper divisors (20044287757311).

140310014301121 is an equidigital number, since it uses as much as digits as its factorization.

140310014301121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20044287757310.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 140310014301121 its reverse (121103410013041), we get a palindrome (261413424314162).

The spelling of 140310014301121 in words is "one hundred forty trillion, three hundred ten billion, fourteen million, three hundred one thousand, one hundred twenty-one".