Base | Representation |
---|---|
bin | 10100011010110000001… |
… | …000101101100001110111 |
3 | 11222010200110022022210001 |
4 | 110122300020231201313 |
5 | 140442034242142101 |
6 | 2552325403212131 |
7 | 203241324501604 |
oct | 24326010554167 |
9 | 4863613268701 |
10 | 1403114412151 |
11 | 4a106a563231 |
12 | 1a7b24217047 |
13 | a240bc09aba |
14 | 4bca80b56ab |
15 | 267717a3901 |
hex | 146b022d877 |
1403114412151 has 2 divisors, whose sum is σ = 1403114412152. Its totient is φ = 1403114412150.
The previous prime is 1403114412103. The next prime is 1403114412191. The reversal of 1403114412151 is 1512144113041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1403114412151 is a prime.
It is a super-3 number, since 3×14031144121513 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1403114412191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701557206075 + 701557206076.
It is an arithmetic number, because the mean of its divisors is an integer number (701557206076).
Almost surely, 21403114412151 is an apocalyptic number.
1403114412151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1403114412151 is an equidigital number, since it uses as much as digits as its factorization.
1403114412151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 28.
Adding to 1403114412151 its reverse (1512144113041), we get a palindrome (2915258525192).
The spelling of 1403114412151 in words is "one trillion, four hundred three billion, one hundred fourteen million, four hundred twelve thousand, one hundred fifty-one".
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