1403117113 has 4 divisors (see below), whose sum is σ = 1408075408. Its totient is φ = 1398158820.

The previous prime is 1403117081. The next prime is 1403117119. The reversal of 1403117113 is 3117113041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1403117113 - 2⁵ = 1403117081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1403117119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2478723 + ... + 2479288.

It is an arithmetic number, because the mean of its divisors is an integer number (352018852).

Almost surely, 2^1403117113 is an apocalyptic number.

It is an amenable number.

1403117113 is a deficient number, since it is larger than the sum of its proper divisors (4958295).

1403117113 is an equidigital number, since it uses as much as digits as its factorization.

1403117113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4958294.

The product of its (nonzero) digits is 252, while the sum is 22.

The square root of 1403117113 is about 37458.2048822418. The cubic root of 1403117113 is about 1119.5185837565.

The spelling of 1403117113 in words is "one billion, four hundred three million, one hundred seventeen thousand, one hundred thirteen".