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14031215345351 = 108499129321149
BaseRepresentation
bin1100110000101110010110…
…0110110011111011000111
31211200101000112002210112102
43030023211212303323013
53314341412112022401
645501503520142315
72645502411406241
oct314134546637307
954611015083472
1014031215345351
11451a6722a6666
1216a741576799b
137aa1a40540b9
1436718607d091
15194eb659456b
hexcc2e59b3ec7

14031215345351 has 4 divisors (see below), whose sum is σ = 14031344775000. Its totient is φ = 14031085915704.

The previous prime is 14031215345263. The next prime is 14031215345383. The reversal of 14031215345351 is 15354351213041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14031215345351 - 226 = 14031148236487 is a prime.

It is a super-2 number, since 2×140312153453512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14031215345951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64552076 + ... + 64769073.

It is an arithmetic number, because the mean of its divisors is an integer number (3507836193750).

Almost surely, 214031215345351 is an apocalyptic number.

14031215345351 is a deficient number, since it is larger than the sum of its proper divisors (129429649).

14031215345351 is a wasteful number, since it uses less digits than its factorization.

14031215345351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129429648.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 14031215345351 its reverse (15354351213041), we get a palindrome (29385566558392).

The spelling of 14031215345351 in words is "fourteen trillion, thirty-one billion, two hundred fifteen million, three hundred forty-five thousand, three hundred fifty-one".

Divisors: 1 108499 129321149 14031215345351