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14031233341 = 15789370913
BaseRepresentation
bin11010001000101001…
…11010000100111101
31100012212020111122221
431010110322010331
5212213443431331
610240150005341
71004464341556
oct150424720475
940185214587
1014031233341
115a502a1314
122877046851
131427c26348
149716c732d
15571c52711
hex34453a13d

14031233341 has 4 divisors (see below), whose sum is σ = 14120604412. Its totient is φ = 13941862272.

The previous prime is 14031233263. The next prime is 14031233347. The reversal of 14031233341 is 14333213041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4754654116 + 9276579225 = 68954^2 + 96315^2 .

It is a cyclic number.

It is not a de Polignac number, because 14031233341 - 213 = 14031225149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14031233347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44685300 + ... + 44685613.

It is an arithmetic number, because the mean of its divisors is an integer number (3530151103).

Almost surely, 214031233341 is an apocalyptic number.

It is an amenable number.

14031233341 is a deficient number, since it is larger than the sum of its proper divisors (89371071).

14031233341 is an equidigital number, since it uses as much as digits as its factorization.

14031233341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89371070.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14031233341 its reverse (14333213041), we get a palindrome (28364446382).

The spelling of 14031233341 in words is "fourteen billion, thirty-one million, two hundred thirty-three thousand, three hundred forty-one".

Divisors: 1 157 89370913 14031233341