Base | Representation |
---|---|
bin | 1100110000101110110100… |
… | …0011111001010111100101 |
3 | 1211200101100020102202110002 |
4 | 3030023231003321113211 |
5 | 3314342141121112331 |
6 | 45501524144511045 |
7 | 2645505460424222 |
oct | 314135503712745 |
9 | 54611306382402 |
10 | 14031340410341 |
11 | 451a726957861 |
12 | 16a744b61b485 |
13 | 7aa1c3c32557 |
14 | 367198916949 |
15 | 194ec254a9cb |
hex | cc2ed0f95e5 |
14031340410341 has 4 divisors (see below), whose sum is σ = 14031591730272. Its totient is φ = 14031089090412.
The previous prime is 14031340410313. The next prime is 14031340410407. The reversal of 14031340410341 is 14301404313041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14031340410341 - 242 = 9633293899237 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14031340410041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125576201 + ... + 125687886.
It is an arithmetic number, because the mean of its divisors is an integer number (3507897932568).
Almost surely, 214031340410341 is an apocalyptic number.
It is an amenable number.
14031340410341 is a deficient number, since it is larger than the sum of its proper divisors (251319931).
14031340410341 is an equidigital number, since it uses as much as digits as its factorization.
14031340410341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 251319930.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14031340410341 its reverse (14301404313041), we get a palindrome (28332744723382).
The spelling of 14031340410341 in words is "fourteen trillion, thirty-one billion, three hundred forty million, four hundred ten thousand, three hundred forty-one".
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