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14031422134 = 27015711067
BaseRepresentation
bin11010001000101011…
…01000001010110110
31100012212121002122021
431010111220022312
5212214021002014
610240154023354
71004466056152
oct150425501266
940185532567
1014031422134
115a50410144
122877117b5a
131427c91262
14971736062
15571c8d624
hex3445682b6

14031422134 has 4 divisors (see below), whose sum is σ = 21047133204. Its totient is φ = 7015711066.

The previous prime is 14031422123. The next prime is 14031422177. The reversal of 14031422134 is 43122413041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43122413041 = 44996041009.

It is a super-2 number, since 2×140314221342 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14031422099 and 14031422108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3507855532 + ... + 3507855535.

It is an arithmetic number, because the mean of its divisors is an integer number (5261783301).

Almost surely, 214031422134 is an apocalyptic number.

14031422134 is a deficient number, since it is larger than the sum of its proper divisors (7015711070).

14031422134 is an equidigital number, since it uses as much as digits as its factorization.

14031422134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7015711069.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14031422134 its reverse (43122413041), we get a palindrome (57153835175).

The spelling of 14031422134 in words is "fourteen billion, thirty-one million, four hundred twenty-two thousand, one hundred thirty-four".

Divisors: 1 2 7015711067 14031422134