14031610213 has 4 divisors (see below), whose sum is σ = 14034163680. Its totient is φ = 14029056748.

The previous prime is 14031610211. The next prime is 14031610249. The reversal of 14031610213 is 31201613041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31201613041 = 59 ⋅528840899.

It is a cyclic number.

It is not a de Polignac number, because 14031610213 - 2¹ = 14031610211 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14031610211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1268473 + ... + 1279486.

It is an arithmetic number, because the mean of its divisors is an integer number (3508540920).

Almost surely, 2^14031610213 is an apocalyptic number.

It is an amenable number.

14031610213 is a deficient number, since it is larger than the sum of its proper divisors (2553467).

14031610213 is an equidigital number, since it uses as much as digits as its factorization.

14031610213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2553466.

The product of its (nonzero) digits is 432, while the sum is 22.

The spelling of 14031610213 in words is "fourteen billion, thirty-one million, six hundred ten thousand, two hundred thirteen".