Base | Representation |
---|---|
bin | 10100011010110101110… |
… | …101011110110010010011 |
3 | 11222010221010020102201222 |
4 | 110122311311132302103 |
5 | 140442233232044243 |
6 | 2552343100515255 |
7 | 203243565331466 |
oct | 24326565366223 |
9 | 4863833212658 |
10 | 1403210034323 |
11 | 4a1109534619 |
12 | 1a7b5024bb2b |
13 | a2425979a76 |
14 | 4bcb6a872dd |
15 | 26779d91168 |
hex | 146b5d5ec93 |
1403210034323 has 2 divisors, whose sum is σ = 1403210034324. Its totient is φ = 1403210034322.
The previous prime is 1403210034301. The next prime is 1403210034329. The reversal of 1403210034323 is 3234300123041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1403210034323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1403210034292 and 1403210034301.
It is not a weakly prime, because it can be changed into another prime (1403210034329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701605017161 + 701605017162.
It is an arithmetic number, because the mean of its divisors is an integer number (701605017162).
Almost surely, 21403210034323 is an apocalyptic number.
1403210034323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1403210034323 is an equidigital number, since it uses as much as digits as its factorization.
1403210034323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1403210034323 its reverse (3234300123041), we get a palindrome (4637510157364).
The spelling of 1403210034323 in words is "one trillion, four hundred three billion, two hundred ten million, thirty-four thousand, three hundred twenty-three".
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