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14032343200201 = 17825431952953
BaseRepresentation
bin1100110000110010100011…
…0101001111000111001001
31211200110221010100202112021
43030030220311033013021
53314401214324401301
645502211450044441
72645542355124634
oct314145065170711
954613833322467
1014032343200201
1145200a0a06707
1216a768b419721
137aa323908531
14367251b8cc1b
151950305cd8a1
hexcc328d4f1c9

14032343200201 has 4 divisors (see below), whose sum is σ = 14857775153172. Its totient is φ = 13206911247232.

The previous prime is 14032343200189. The next prime is 14032343200223. The reversal of 14032343200201 is 10200234323041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5803184640400 + 8229158559801 = 2408980^2 + 2868651^2 .

It is a cyclic number.

It is not a de Polignac number, because 14032343200201 - 231 = 14030195716553 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14032343200231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412715976460 + ... + 412715976493.

It is an arithmetic number, because the mean of its divisors is an integer number (3714443788293).

Almost surely, 214032343200201 is an apocalyptic number.

It is an amenable number.

14032343200201 is a deficient number, since it is larger than the sum of its proper divisors (825431952971).

14032343200201 is an equidigital number, since it uses as much as digits as its factorization.

14032343200201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 825431952970.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 14032343200201 its reverse (10200234323041), we get a palindrome (24232577523242).

The spelling of 14032343200201 in words is "fourteen trillion, thirty-two billion, three hundred forty-three million, two hundred thousand, two hundred one".

Divisors: 1 17 825431952953 14032343200201