14032410144421 has 4 divisors (see below), whose sum is σ = 14032437469344. Its totient is φ = 14032382819500.

The previous prime is 14032410144407. The next prime is 14032410144437. The reversal of 14032410144421 is 12444101423041.

14032410144421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14032410144421 - 2¹⁵ = 14032410111653 is a prime.

It is a super-3 number, since 3×14032410144421³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14032410144721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12877105 + ... + 13924246.

It is an arithmetic number, because the mean of its divisors is an integer number (3508109367336).

Almost surely, 2^{14032410144421} is an apocalyptic number.

It is an amenable number.

14032410144421 is a deficient number, since it is larger than the sum of its proper divisors (27324923).

14032410144421 is an equidigital number, since it uses as much as digits as its factorization.

14032410144421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27324922.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 14032410144421 its reverse (12444101423041), we get a palindrome (26476511567462).

The spelling of 14032410144421 in words is "fourteen trillion, thirty-two billion, four hundred ten million, one hundred forty-four thousand, four hundred twenty-one".