Base | Representation |
---|---|
bin | 11010001000110010… |
… | …11010001001110111 |
3 | 1100012221110110021020 |
4 | 31010121122021313 |
5 | 212214244211203 |
6 | 10240231152223 |
7 | 1004510354646 |
oct | 150431321167 |
9 | 40187413236 |
10 | 14032413303 |
11 | 5a50a27897 |
12 | 2877515673 |
13 | 142824a44c |
14 | 97191335d |
15 | 571dd7153 |
hex | 34465a277 |
14032413303 has 16 divisors (see below), whose sum is σ = 19217669856. Its totient is φ = 9102274560.
The previous prime is 14032413301. The next prime is 14032413313. The reversal of 14032413303 is 30331423041.
14032413303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14032413303 - 21 = 14032413301 is a prime.
It is a super-2 number, since 2×140324133032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14032413301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 107050 + ... + 198807.
It is an arithmetic number, because the mean of its divisors is an integer number (1201104366).
Almost surely, 214032413303 is an apocalyptic number.
14032413303 is a deficient number, since it is larger than the sum of its proper divisors (5185256553).
14032413303 is a wasteful number, since it uses less digits than its factorization.
14032413303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 306274.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 14032413303 its reverse (30331423041), we get a palindrome (44363836344).
The spelling of 14032413303 in words is "fourteen billion, thirty-two million, four hundred thirteen thousand, three hundred three".
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