14032421304001 has 4 divisors (see below), whose sum is σ = 14642526578112. Its totient is φ = 13422316029892.

The previous prime is 14032421303993. The next prime is 14032421304023. The reversal of 14032421304001 is 10040312423041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14032421304001 - 2³ = 14032421303993 is a prime.

It is a super-2 number, since 2×14032421304001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14032421304401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305052637021 + ... + 305052637066.

It is an arithmetic number, because the mean of its divisors is an integer number (3660631644528).

Almost surely, 2^{14032421304001} is an apocalyptic number.

It is an amenable number.

14032421304001 is a deficient number, since it is larger than the sum of its proper divisors (610105274111).

14032421304001 is an equidigital number, since it uses as much as digits as its factorization.

14032421304001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 610105274110.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14032421304001 its reverse (10040312423041), we get a palindrome (24072733727042).

The spelling of 14032421304001 in words is "fourteen trillion, thirty-two billion, four hundred twenty-one million, three hundred four thousand, one".