Base | Representation |
---|---|
bin | 1100110000110010111000… |
… | …1100101000100111001011 |
3 | 1211200111011101202020112111 |
4 | 3030030232030220213023 |
5 | 3314401410401020133 |
6 | 45502224423323151 |
7 | 2645544530232310 |
oct | 314145614504713 |
9 | 54614141666474 |
10 | 14032433220043 |
11 | 4520137800977 |
12 | 16a76b55b04b7 |
13 | 7aa339466504 |
14 | 36725db02d07 |
15 | 1950384611cd |
hex | cc32e3289cb |
14032433220043 has 4 divisors (see below), whose sum is σ = 16037066537200. Its totient is φ = 12027799902888.
The previous prime is 14032433220031. The next prime is 14032433220049. The reversal of 14032433220043 is 34002233423041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14032433220043 - 221 = 14032431122891 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14032433219987 and 14032433220014.
It is not an unprimeable number, because it can be changed into a prime (14032433220049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002316658568 + ... + 1002316658581.
It is an arithmetic number, because the mean of its divisors is an integer number (4009266634300).
Almost surely, 214032433220043 is an apocalyptic number.
14032433220043 is a deficient number, since it is larger than the sum of its proper divisors (2004633317157).
14032433220043 is an equidigital number, since it uses as much as digits as its factorization.
14032433220043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2004633317156.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 14032433220043 its reverse (34002233423041), we get a palindrome (48034666643084).
The spelling of 14032433220043 in words is "fourteen trillion, thirty-two billion, four hundred thirty-three million, two hundred twenty thousand, forty-three".
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