14032440312011 has 24 divisors (see below), whose sum is σ = 15439471750080. Its totient is φ = 12744044593280.

The previous prime is 14032440311959. The next prime is 14032440312017. The reversal of 14032440312011 is 11021304423041.

14032440312011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a de Polignac number, because none of the positive numbers 2^k-14032440312011 is a prime.

It is a super-3 number, since 3×14032440312011³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14032440312017) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1078831070 + ... + 1078844076.

It is an arithmetic number, because the mean of its divisors is an integer number (643311322920).

Almost surely, 2^{14032440312011} is an apocalyptic number.

14032440312011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14032440312011 is a deficient number, since it is larger than the sum of its proper divisors (1407031438069).

14032440312011 is a wasteful number, since it uses less digits than its factorization.

14032440312011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21235 (or 21224 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14032440312011 its reverse (11021304423041), we get a palindrome (25053744735052).

The spelling of 14032440312011 in words is "fourteen trillion, thirty-two billion, four hundred forty million, three hundred twelve thousand, eleven".