140330433011 has 2 divisors, whose sum is σ = 140330433012. Its totient is φ = 140330433010.

The previous prime is 140330432999. The next prime is 140330433017. The reversal of 140330433011 is 110334033041.

140330433011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140330433011 - 2¹⁸ = 140330170867 is a prime.

It is a super-2 number, since 2×140330433011² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140330433017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70165216505 + 70165216506.

It is an arithmetic number, because the mean of its divisors is an integer number (70165216506).

Almost surely, 2^140330433011 is an apocalyptic number.

140330433011 is a deficient number, since it is larger than the sum of its proper divisors (1).

140330433011 is an equidigital number, since it uses as much as digits as its factorization.

140330433011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 140330433011 its reverse (110334033041), we get a palindrome (250664466052).

The spelling of 140330433011 in words is "one hundred forty billion, three hundred thirty million, four hundred thirty-three thousand, eleven".