140330500012701 has 24 divisors (see below), whose sum is σ = 207982237704696. Its totient is φ = 91122976028160.

The previous prime is 140330500012699. The next prime is 140330500012709. The reversal of 140330500012701 is 107210005033041.

140330500012701 is a `hidden beast` number, since 1 + 4 + 0 + 3 + 30 + 500 + 0 + 127 + 0 + 1 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 43832000089476 + 96498499923225 = 6620574^2 + 9823365^2 .

It is not a de Polignac number, because 140330500012701 - 2¹ = 140330500012699 is a prime.

It is a super-2 number, since 2×140330500012701² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140330500012709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 309969120 + ... + 310421513.

It is an arithmetic number, because the mean of its divisors is an integer number (8665926571029).

Almost surely, 2^{140330500012701} is an apocalyptic number.

It is an amenable number.

140330500012701 is a deficient number, since it is larger than the sum of its proper divisors (67651737691995).

140330500012701 is a wasteful number, since it uses less digits than its factorization.

140330500012701 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 620391293 (or 620391290 counting only the distinct ones).

The product of its (nonzero) digits is 2520, while the sum is 27.

Adding to 140330500012701 its reverse (107210005033041), we get a palindrome (247540505045742).

The spelling of 140330500012701 in words is "one hundred forty trillion, three hundred thirty billion, five hundred million, twelve thousand, seven hundred one".