14033113 has 4 divisors (see below), whose sum is σ = 14140368. Its totient is φ = 13925860.

The previous prime is 14033081. The next prime is 14033141. The reversal of 14033113 is 31133041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133041 = 107 ⋅290963.

It is a cyclic number.

It is not a de Polignac number, because 14033113 - 2⁵ = 14033081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14033183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53431 + ... + 53692.

It is an arithmetic number, because the mean of its divisors is an integer number (3535092).

Almost surely, 2^14033113 is an apocalyptic number.

It is an amenable number.

14033113 is a deficient number, since it is larger than the sum of its proper divisors (107255).

14033113 is a wasteful number, since it uses less digits than its factorization.

14033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107254.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 14033113 is about 3746.0796841498. The cubic root of 14033113 is about 241.2040935677.

Adding to 14033113 its reverse (31133041), we get a palindrome (45166154).

The spelling of 14033113 in words is "fourteen million, thirty-three thousand, one hundred thirteen".