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14033121999397 is a prime number
BaseRepresentation
bin1100110000110101011101…
…0000000111101000100101
31211200112221101210212011221
43030031113100013220211
53314404313212440042
645502421030300341
72645600562611344
oct314152720075045
954615841725157
1014033121999397
114520460587006
1216a78681b76b1
137aa419077567
143672c7399b5b
15195078b68d67
hexcc357407a25

14033121999397 has 2 divisors, whose sum is σ = 14033121999398. Its totient is φ = 14033121999396.

The previous prime is 14033121999361. The next prime is 14033121999419. The reversal of 14033121999397 is 79399912133041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11134227566401 + 2898894432996 = 3336799^2 + 1702614^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14033121999397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14033121999317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016560999698 + 7016560999699.

It is an arithmetic number, because the mean of its divisors is an integer number (7016560999699).

Almost surely, 214033121999397 is an apocalyptic number.

It is an amenable number.

14033121999397 is a deficient number, since it is larger than the sum of its proper divisors (1).

14033121999397 is an equidigital number, since it uses as much as digits as its factorization.

14033121999397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9920232, while the sum is 61.

The spelling of 14033121999397 in words is "fourteen trillion, thirty-three billion, one hundred twenty-one million, nine hundred ninety-nine thousand, three hundred ninety-seven".