Base | Representation |
---|---|
bin | 10100011010111011111… |
… | …111110010100010001011 |
3 | 11222011012022201221201102 |
4 | 110122323333302202023 |
5 | 140442441212244242 |
6 | 2552401232212015 |
7 | 203246262042134 |
oct | 24327377624213 |
9 | 4864168657642 |
10 | 1403313399947 |
11 | 4a1161914758 |
12 | 1a7b7a99a00b |
13 | a24411cb464 |
14 | 4bcc66b2c8b |
15 | 26783eace32 |
hex | 146bbff288b |
1403313399947 has 2 divisors, whose sum is σ = 1403313399948. Its totient is φ = 1403313399946.
The previous prime is 1403313399913. The next prime is 1403313399953. The reversal of 1403313399947 is 7499933133041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1403313399947 - 210 = 1403313398923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1403313399892 and 1403313399901.
It is not a weakly prime, because it can be changed into another prime (1403313399247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701656699973 + 701656699974.
It is an arithmetic number, because the mean of its divisors is an integer number (701656699974).
Almost surely, 21403313399947 is an apocalyptic number.
1403313399947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1403313399947 is an equidigital number, since it uses as much as digits as its factorization.
1403313399947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6613488, while the sum is 56.
The spelling of 1403313399947 in words is "one trillion, four hundred three billion, three hundred thirteen million, three hundred ninety-nine thousand, nine hundred forty-seven".
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