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140331340153 = 6110632164171
BaseRepresentation
bin1000001010110001100…
…1100101000101111001
3111102012221011200222201
42002230121211011321
54244344310341103
6144244535350201
713065353465404
oct2025431450571
9442187150881
10140331340153
1154572423984
1223244822361
1310305413a64
146b1363cd3b
1539b4d7151d
hex20ac665179

140331340153 has 8 divisors (see below), whose sum is σ = 142766098496. Its totient is φ = 137900912400.

The previous prime is 140331340129. The next prime is 140331340157. The reversal of 140331340153 is 351043133041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140331340153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140331340157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1017243 + ... + 1146928.

It is an arithmetic number, because the mean of its divisors is an integer number (17845762312).

Almost surely, 2140331340153 is an apocalyptic number.

It is an amenable number.

140331340153 is a deficient number, since it is larger than the sum of its proper divisors (2434758343).

140331340153 is a wasteful number, since it uses less digits than its factorization.

140331340153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2165295.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 140331340153 its reverse (351043133041), we get a palindrome (491374473194).

The spelling of 140331340153 in words is "one hundred forty billion, three hundred thirty-one million, three hundred forty thousand, one hundred fifty-three".

Divisors: 1 61 1063 64843 2164171 132014431 2300513773 140331340153