1403413004131 has 4 divisors (see below), whose sum is σ = 1403437102200. Its totient is φ = 1403388906064.

The previous prime is 1403413004107. The next prime is 1403413004171. The reversal of 1403413004131 is 1314003143041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1403413004131 - 2¹³ = 1403412995939 is a prime.

It is a super-2 number, since 2×1403413004131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1403413004096 and 1403413004105.

It is not an unprimeable number, because it can be changed into a prime (1403413004101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11961466 + ... + 12078223.

It is an arithmetic number, because the mean of its divisors is an integer number (350859275550).

Almost surely, 2^{1403413004131} is an apocalyptic number.

1403413004131 is a deficient number, since it is larger than the sum of its proper divisors (24098069).

1403413004131 is an equidigital number, since it uses as much as digits as its factorization.

1403413004131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24098068.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1403413004131 its reverse (1314003143041), we get a palindrome (2717416147172).

The spelling of 1403413004131 in words is "one trillion, four hundred three billion, four hundred thirteen million, four thousand, one hundred thirty-one".