140342011333 has 4 divisors (see below), whose sum is σ = 140351941548. Its totient is φ = 140332081120.

The previous prime is 140342011307. The next prime is 140342011339. The reversal of 140342011333 is 333110243041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 53360076004 + 86981935329 = 230998^2 + 294927^2 .

It is a cyclic number.

It is not a de Polignac number, because 140342011333 - 2⁵ = 140342011301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140342011298 and 140342011307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140342011339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4943878 + ... + 4972183.

It is an arithmetic number, because the mean of its divisors is an integer number (35087985387).

Almost surely, 2^140342011333 is an apocalyptic number.

It is an amenable number.

140342011333 is a deficient number, since it is larger than the sum of its proper divisors (9930215).

140342011333 is an equidigital number, since it uses as much as digits as its factorization.

140342011333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9930214.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 140342011333 its reverse (333110243041), we get a palindrome (473452254374).

The spelling of 140342011333 in words is "one hundred forty billion, three hundred forty-two million, eleven thousand, three hundred thirty-three".