14034334000327 has 2 divisors, whose sum is σ = 14034334000328. Its totient is φ = 14034334000326.

The previous prime is 14034334000249. The next prime is 14034334000343. The reversal of 14034334000327 is 72300043343041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14034334000327 - 2³¹ = 14032186516679 is a prime.

It is a super-3 number, since 3×14034334000327³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14034334000292 and 14034334000301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14034334000387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017167000163 + 7017167000164.

It is an arithmetic number, because the mean of its divisors is an integer number (7017167000164).

Almost surely, 2^{14034334000327} is an apocalyptic number.

14034334000327 is a deficient number, since it is larger than the sum of its proper divisors (1).

14034334000327 is an equidigital number, since it uses as much as digits as its factorization.

14034334000327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 34.

Adding to 14034334000327 its reverse (72300043343041), we get a palindrome (86334377343368).

The spelling of 14034334000327 in words is "fourteen trillion, thirty-four billion, three hundred thirty-four million, three hundred twenty-seven", and thus it is an aban number.