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14034402020311 is a prime number
BaseRepresentation
bin1100110000111010001110…
…0011000000101111010111
31211200200020121101122202221
43030032203203000233113
53314414423404122221
645503152033443211
72645644364610631
oct314164343005727
954620217348687
1014034402020311
114520a58078732
1216a7b64a10507
137aa59130879a
143673a9399a51
1519510120e541
hexcc3a38c0bd7

14034402020311 has 2 divisors, whose sum is σ = 14034402020312. Its totient is φ = 14034402020310.

The previous prime is 14034402020299. The next prime is 14034402020333. The reversal of 14034402020311 is 11302020443041.

14034402020311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14034402020311 - 229 = 14033865149399 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14034402060311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017201010155 + 7017201010156.

It is an arithmetic number, because the mean of its divisors is an integer number (7017201010156).

Almost surely, 214034402020311 is an apocalyptic number.

14034402020311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14034402020311 is an equidigital number, since it uses as much as digits as its factorization.

14034402020311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14034402020311 its reverse (11302020443041), we get a palindrome (25336422463352).

The spelling of 14034402020311 in words is "fourteen trillion, thirty-four billion, four hundred two million, twenty thousand, three hundred eleven".