Base | Representation |
---|---|
bin | 1100110000111100111100… |
… | …0001000000110111000011 |
3 | 1211200202010102200011212012 |
4 | 3030033033001000313003 |
5 | 3314422422103233121 |
6 | 45503352244523135 |
7 | 2646001431462356 |
oct | 314171701006703 |
9 | 54622112604765 |
10 | 14035131305411 |
11 | 45212a17aa397 |
12 | 16a81290b04ab |
13 | 7aa67942c628 |
14 | 36743819829d |
15 | 195145268c5b |
hex | cc3cf040dc3 |
14035131305411 has 2 divisors, whose sum is σ = 14035131305412. Its totient is φ = 14035131305410.
The previous prime is 14035131305407. The next prime is 14035131305417. The reversal of 14035131305411 is 11450313153041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14035131305411 - 22 = 14035131305407 is a prime.
It is not a weakly prime, because it can be changed into another prime (14035131305417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017565652705 + 7017565652706.
It is an arithmetic number, because the mean of its divisors is an integer number (7017565652706).
Almost surely, 214035131305411 is an apocalyptic number.
14035131305411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14035131305411 is an equidigital number, since it uses as much as digits as its factorization.
14035131305411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 14035131305411 its reverse (11450313153041), we get a palindrome (25485444458452).
The spelling of 14035131305411 in words is "fourteen trillion, thirty-five billion, one hundred thirty-one million, three hundred five thousand, four hundred eleven".
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