Base | Representation |
---|---|
bin | 1100110000111100111100… |
… | …0001000000110111001001 |
3 | 1211200202010102200011212102 |
4 | 3030033033001000313021 |
5 | 3314422422103233132 |
6 | 45503352244523145 |
7 | 2646001431462365 |
oct | 314171701006711 |
9 | 54622112604772 |
10 | 14035131305417 |
11 | 45212a17aa3a2 |
12 | 16a81290b04b5 |
13 | 7aa67942c631 |
14 | 3674381982a5 |
15 | 195145268c62 |
hex | cc3cf040dc9 |
14035131305417 has 2 divisors, whose sum is σ = 14035131305418. Its totient is φ = 14035131305416.
The previous prime is 14035131305411. The next prime is 14035131305453. The reversal of 14035131305417 is 71450313153041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9564397428496 + 4470733876921 = 3092636^2 + 2114411^2 .
It is a cyclic number.
It is not a de Polignac number, because 14035131305417 - 26 = 14035131305353 is a prime.
It is not a weakly prime, because it can be changed into another prime (14035131305411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7017565652708 + 7017565652709.
It is an arithmetic number, because the mean of its divisors is an integer number (7017565652709).
Almost surely, 214035131305417 is an apocalyptic number.
It is an amenable number.
14035131305417 is a deficient number, since it is larger than the sum of its proper divisors (1).
14035131305417 is an equidigital number, since it uses as much as digits as its factorization.
14035131305417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 38.
Adding to 14035131305417 its reverse (71450313153041), we get a palindrome (85485444458458).
The spelling of 14035131305417 in words is "fourteen trillion, thirty-five billion, one hundred thirty-one million, three hundred five thousand, four hundred seventeen".
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