14035140405311 has 4 divisors (see below), whose sum is σ = 14361539019432. Its totient is φ = 13708741791192.

The previous prime is 14035140405271. The next prime is 14035140405323. The reversal of 14035140405311 is 11350404153041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14035140405311 - 2²² = 14035136211007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14035140405511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163199306996 + ... + 163199307081.

It is an arithmetic number, because the mean of its divisors is an integer number (3590384754858).

Almost surely, 2^{14035140405311} is an apocalyptic number.

14035140405311 is a deficient number, since it is larger than the sum of its proper divisors (326398614121).

14035140405311 is an equidigital number, since it uses as much as digits as its factorization.

14035140405311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 326398614120.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 14035140405311 its reverse (11350404153041), we get a palindrome (25385544558352).

The spelling of 14035140405311 in words is "fourteen trillion, thirty-five billion, one hundred forty million, four hundred five thousand, three hundred eleven".