14035142041 has 4 divisors (see below), whose sum is σ = 14645365632. Its totient is φ = 13424918452.

The previous prime is 14035141997. The next prime is 14035142057. The reversal of 14035142041 is 14024153041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14024153041 = 4549 ⋅3082909.

It is a cyclic number.

It is not a de Polignac number, because 14035142041 - 2²¹ = 14033044889 is a prime.

It is a super-2 number, since 2×14035142041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14035141997 and 14035142015.

It is not an unprimeable number, because it can be changed into a prime (14035142741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305111761 + ... + 305111806.

It is an arithmetic number, because the mean of its divisors is an integer number (3661341408).

Almost surely, 2^14035142041 is an apocalyptic number.

It is an amenable number.

14035142041 is a deficient number, since it is larger than the sum of its proper divisors (610223591).

14035142041 is an equidigital number, since it uses as much as digits as its factorization.

14035142041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 610223590.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14035142041 its reverse (14024153041), we get a palindrome (28059295082).

The spelling of 14035142041 in words is "fourteen billion, thirty-five million, one hundred forty-two thousand, forty-one".